Odds for the 2015 NFL playoff final, presented from the AFC team’s point of view:
|SuperBowl Playoff Odds|
|Prediction Method||AFC Team||NFC Team||Score Diff||Win Prob||Est. Point Spread|
|C&F Playoff Model||Denver Broncos||Carolina Panthers||2.097||0.891||15.5|
|Pythagorean Expectations||Denver Broncos||Carolina Panthers||-0.173||0.295||-6.4|
|Simple Ranking||Denver Broncos||Carolina Panthers||-2.3||0.423||-2.3|
|Median Point Spread||Denver Broncos||Carolina Panthers||-5.0||0.337||-5.0|
Last week the system went 1-1, for a total record of 6-4. The system favors Denver more than any other team, and does not like Carolina at all. Understand, when a team makes it to the Super Bowl easily, and a predictive system gave them about a 3% chance to get there in the first place, it’s reasonable to assume that in that instance, the system really isn’t working.
So we’re going to modify our table a little bit and give some other predictions and predictive methods. The first is the good old Pythagorean formula. We best fit the Pythagorean exponent to the data for the year, so there is good reason to believe that it is more accurate than the old 2.37. It favors Carolina by a little more than six points. SRS directly gives point spread, which can be back calculated into a 57.7% chance of Carolina winning. Likewise, using median point spreads to predict the Denver-Carolina game gives Carolina a 66.3% chance of winning.
Note that none of these systems predicted the outcome of the Carolina – Arizona game. Arizona played a tougher schedule and was more of a regular season statistical powerhouse than Carolina. Arizona, however, began to lose poise as it worked its way through the playoffs. And it lost a lot of poise in the NFC championship game.